Câu 9 :
\(X:Fe\left(xmol\right),O\left(ymol\right)\)
\(m_X=56x+16y=4.5\left(g\right)\left(1\right)\)
\(n_{SO_2}=\dfrac{1.26}{22.4}=0.05625\left(mol\right)\)
Bảo toàn e :
\(3x=2y+0.05625\cdot2\left(2\right)\)
\(\left(1\right),\left(2\right):x=0.0675,y=0.045\)
\(m_{Fe}=0.0675\cdot56=3.78\left(g\right)\)
Câu 10 :
\(n_{Fe}=\dfrac{6.72}{56}=0.12\left(mol\right)\)
\(\Rightarrow n_{Fe\left(dư\right)}=0.12-0.1=0.02\left(mol\right)\)
\(n_{Fe_2\left(SO_4\right)_3}=\dfrac{0.3}{6}=0.05\left(mol\right)\)
\(Fe+Fe_2\left(SO_4\right)_3\rightarrow3FeSO_4\)
\(0.02........0.02............0.06\)
\(n_{Fe_2\left(SO_4\right)_3\left(cl\right)}=0.05-0.02=0.03\left(mol\right)\)
\(Cu+Fe_2\left(SO_4\right)_3\rightarrow CuSO_4+2FeSO_4\)
\(0.03...........0.03\)
\(m_{Cu}=0.03\cdot64=1.92\left(g\right)\)
