Bài 6: Lũy thừa của một số hữu tỉ (tiếp theo...)

Tìm x dễ tự làm:

\(3^{n+3}+3^{n+1}+2^{n+3}+2^{n+2}\)

\(=3^n.3^3+3^n.3^1+2^n.2^3+2^n.2^2\)

\(=3^n.9+3^n.3+2^n.8+2^n.4\)

\(=3^n\left(9+3\right)+2^n\left(8+4\right)\)

\(=3^n.12+2^n.12\)

\(=12\left(3^n+2^n\right)\)

\(=6.2\left(3^n+2^n\right)⋮6\rightarrowđpcm\)

https://hoc24.vn/hoi-dap/question/462129.html?pos=1207827

vào link này làm hộ mik bài 3 nha

a,Ta có \(\left(3^3\right)^n:3^n=9\Leftrightarrow3^{3n}:3^n=3^2\Leftrightarrow3n-n=2\Leftrightarrow n=1\)

b,TA có \(\dfrac{5^2}{5^n}=5^1\Leftrightarrow2-n=1\Leftrightarrow n=1\)

Các câu sau để bn tự làm

a) 27ⁿ : 3ⁿ = 9

\(\Leftrightarrow\) (27 : 3)ⁿ = 9

\(\Leftrightarrow\) 9ⁿ = 9

\(\Leftrightarrow\) n = 1

b) \(\dfrac{25}{5^n}=5\)

\(\Leftrightarrow\dfrac{5^2}{5^n}=5\)

\(\Leftrightarrow5^n.5=5^2\)

\(\Leftrightarrow5^{n+1}=5^2\)

\(\Leftrightarrow n+1=2\)

n = 2 - 1

n = 1

c) \(\dfrac{81}{\left(-3\right)^n}=-243\)

\(\Leftrightarrow\dfrac{\left(-3\right)^4}{\left(-3\right)^n}=\left(-3\right)^5\)

\(\Leftrightarrow\left(-3\right)^n.\left(-3\right)^5=\left(-3\right)^4\)

\(\Leftrightarrow\left(-3\right)^{n+5}=\left(-3\right)^4\)

\(\Leftrightarrow n+5=4\)

n = 4 - 5

n = -1

a, \(5^x+5^{x+1}+5^{x-2}=151\)

\(\Rightarrow5^x.\left(1+5+5^{-2}\right)=151\)

\(\Rightarrow5^x.6,04=151\Rightarrow5^x=25=5^2\)

Vì \(5\ne-1;5\ne0;5\ne1\) nên \(x=2\)

b, \(5^{x-1}+5^{x-2}+5^{x-3}=155\)

\(\Rightarrow5^x.\left(5^{-1}+5^{-2}+5^{-3}\right)=155\)

\(\Rightarrow5^x.0,248=155\Rightarrow5^x=625=5^4\)

Vì \(5\ne-1;5\ne0;5\ne1\) nên \(x=4\)

\(•5^x+5^{x+1}+5^{x-2}=151\\ 5^x\left(1+5+\dfrac{1}{25}\right)=151\\ 5^x=25\\ \Rightarrow x=2\)

\(•5^{x-1}+5^{x-2}+5^{x-3}=155\\ 5^x.\left(\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}\right)=155\\ 5^x=625\\ \Rightarrow x=4\)

\(•5^{2+x}+5^{3+x}=750\\ 5^x\left(25+125\right)=750\\ 5^x=5\\ \Rightarrow x=1\)

a) (3/7)²¹: (9/49)⁶

= (3/7)²¹: (3²/7²)⁶

⁼ (3/7)²¹: (3/7)¹²

= (3/7)^21-12

= (3/7)⁹

45^10*5^20/75^15

=(3^2*5)^10*5^20/(3*5^2)^15

=3^20*5^10*5^20/3^15*5^30

=3^20*5^30/3^15*5^30

=3^5=243

Bạn gõ tên mấy bài tập đó ra rồi tìm trên hoc24 cx có đó bạn

b) 81⁷ - 27⁹ -9¹³ chia hết cho 405

Ta có: 81⁷ - 27⁹ -9¹³ = 3²⁸- 3²⁷-3²⁶

⁼ 3²⁶(3²-3-1)

= 3²⁶. 5 = 3²². 405 chia hết cho 405 (đpcm)

a)

\(7^6+7^5-7^4=7^4.\left(7^2+7-1\right)=7^4.55\) chia hết cho 55

=>\(7^6+7^5-7^4\) chia hết cho 55

c)

\(16^5+2^{15}=2^{4.5}+2^{15}=2^{20}+2^{15}=2^{15}.\left(2^5+1\right)=2^{15}.33\)chia hết cho 33

Do đó: \(16^5+2^{15}\) chia hết cho 33

\(M=\dfrac{1}{3}+\dfrac{2}{3^2}+...+\dfrac{100}{3^{100}}\)

\(\Rightarrow3M=1+\dfrac{2}{3}+\dfrac{3}{3^2}+...+\dfrac{100}{3^{99}}\)

\(\Rightarrow3M-M=\left(1+\dfrac{2}{3}+\dfrac{3}{3^2}+...+\dfrac{100}{3^{99}}\right)-\left(\dfrac{1}{3}+\dfrac{2}{3^2}+...+\dfrac{100}{3^{100}}\right)\)

\(\Rightarrow2M=1+\left(\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{99}}\right)-\dfrac{100}{3^{100}}\)

\(\Rightarrow2M=1+\dfrac{1}{2}-\dfrac{1}{3^{99}.2}-\dfrac{100}{3^{100}}\)

\(\Rightarrow M=\dfrac{3}{4}-\dfrac{1}{3^{99}.4}-\dfrac{50}{3^{100}}< \dfrac{3}{4}\)

Vậy...

\(\text{a) }\dfrac{\left(-6\right)^6}{216}=\dfrac{6^6}{216}=\dfrac{6^6}{6^3}=6^3=216\)

\(\text{b) }\dfrac{64}{\left(-4\right)^5}=-\dfrac{64}{4^5}=-\dfrac{4^3}{4^5}=-\dfrac{1}{4^2}=-\dfrac{1}{16}\)

\(\text{c) }\dfrac{900}{\left(-30\right)^3}=-\dfrac{900}{30^3}=-\dfrac{30^2}{30^3}=-\dfrac{1}{30}\)

\(\text{d) }\dfrac{225}{15^3}=\dfrac{15^2}{15^3}=\dfrac{1}{15}\)

Đề nghị bạn trình bày câu hỏi rõ ràng hơn nữa

\(x^{-n}=\dfrac{1}{x^n}\Leftrightarrow x^{-n}\cdot x^n=1\)

Thấy: \(x^{-n};x^n\) là 2 số đối nhau

Suy ra \(x^{-n}\cdot x^n=1\)