Question

 

\(y=\sqrt{19-8\sqrt{3}}\) + \(\sqrt{19-8\sqrt{3}}\). Tính y = ?

 

Answer 1

\(=2\sqrt{16-2.4.\sqrt{3}+3}=2\sqrt{\left(4-\sqrt{3}\right)^2}=8-2\sqrt{3}\)

Answer 2

\(y=\sqrt{19-8\sqrt{3}}+\sqrt{19-8\sqrt{3}}\)

\(=\sqrt{19-\sqrt{192}}+\sqrt{19-\sqrt{192}}\)

\(=2\sqrt{19-\sqrt{192}}\)

Mik mới hok lớp 9 nếu sai thông cảm nha

Thanks

Answer 3

Mik triều 19 ko phải 16

Answer 4

o0o I am a studious person o0o 19 tách ra 16+3 đấy

Answer 5

\(y=\sqrt{16+3-2.3\sqrt{3}}+\sqrt{16+3-2.3\sqrt{3}}=\sqrt{\left(4-\sqrt{3}\right)}+\sqrt{\left(4-\sqrt{3}\right)}\)

\(=8-2\sqrt{3}\)

Answer 6

ủa sao trả lời hết rồi