\(\left(x+y+z\right)^2=\left[\left(x+y\right)+z\right]^2\)
\(=\left(x+y\right)^2+z^2+2\left(x+y\right)z\)
\(=x^2+2xy+y^2+z^2+2xz+2yz\)
\(=x^2+y^2+z^2+2xy+2yz+2xz\)
Bài giải
\(\left(x+y+z\right)^2=\left[\left(x+y\right)+z\right]^2=\left(x+y\right)^2+2\left(x+y\right)z+z^2\)
\(=x^2+2xy+y^2+2xz+2yz+z^2\)
\(=x^2+y^2+z^2+2xy+2yz+2xz\)