Question

x.(x+1)=2+4+6+...+2500

Answer 1

x.(x + 1) = 2 + 4 + 6 + ... + 2500

x.(x + 1) = 2.(1 + 2 + 3 + ... + 1250)

x.(x + 1) = 2.(1 + 1250).1250 : 2

x.(x + 1) = 1250.1251

=> x = 1250

Vậy x = 1250 

Answer 2

\(x\times\left(x+1\right)=2+4+6+...+2500\)
\(x\times\left(x+1\right)=2\times\left(1+2+3+...+1250\right)\)
\(x\times\left(x+1\right)=2\times\left(1+1250\right)\times1250\div2\)
\(x\times\left(x+1\right)=1250\times1251\)
\(\Rightarrow x=1250\)
 

Answer 3

x.(x+1)=2+4+6+...+2500

=>x.(x+1)=(2500+2).[(2500-2):2+1]:2

=>x.(x+1)=2502.1250:2

=>x.(x+1)=1251.2.1250:2

=>x.(x+1)=1251.1250

Vì x<x+1

=>x=1250

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Answer 4

x.(x + 1) = 2 + 4 + 6 + ... + 2500

x.(x + 1) = 2.(1 + 2 + 3 + ... + 1250)

x.(x + 1) = 2.(1 + 1250).1250 : 2

x.(x + 1) = 1250.1251

=> x = 1250

Vậy x = 1250