Question

Xin giải giúp:

1. \(\left(x-\frac{5}{24}\right)\frac{18}{7}=-\frac{12}{7}\)

2. \(\frac{3}{4}+\frac{1}{4}\left(x-1\right)=\frac{1}{2}\)

3. \(\left(4x-\frac{1}{2}\right)\left(\frac{x}{3}-\frac{1}{5}\right)=0\)

Xin cảm ơn!!

Answer 1

* \(\left(x-\frac{5}{24}\right)\cdot\frac{18}{7}=-\frac{12}{7}\)

<=> \(x-\frac{5}{24}=-\frac{2}{3}\)

<=> \(x=-\frac{11}{24}\)

* \(\frac{3}{4}+\frac{1}{4}\left(x-1\right)=\frac{1}{2}\)

<=> \(\frac{x-1}{4}=\frac{-1}{4}\)

<=> \(x-1=-1\)

<=> \(x=0\)

* \(\left(4x-\frac{1}{2}\right)\left(\frac{x}{3}-\frac{1}{5}\right)=0\)

<=> \(\orbr{\begin{cases}4x-\frac{1}{2}=0\\\frac{x}{3}-\frac{1}{5}=0\end{cases}}\)<=> \(\orbr{\begin{cases}4x=\frac{1}{2}\\\frac{x}{3}=\frac{1}{5}\end{cases}}\)<=> \(\orbr{\begin{cases}x=\frac{1}{8}\\x=\frac{3}{5}\end{cases}}\)