đáp án bằng 51/92
đúng 100%
tích cho tui nha
cảm ơn
tui bị trừ 50 điểm rồi
nhớ ủng hộ nha
huhu
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2+\frac{1}{6}-\frac{1}{4}=\frac{7}{46}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2+\frac{1}{6}=\frac{7}{46}+\frac{1}{4}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2=\frac{37}{92}-\frac{1}{6}\)
\(x+\frac{1}{4}-\frac{1}{3}=\frac{65}{276}.2\)
\(x+\frac{1}{4}-\frac{1}{3}=\frac{65}{138}\)
\(x+\frac{1}{4}=\frac{37}{46}\)
\(x=\frac{37}{46}-\frac{1}{4}=\frac{51}{92}\)
thôi huhu tui đang tìm điểm giúp đi huhu khóc huhu
Ta có :
(x + \(\frac{1}{4}\)- \(\frac{1}{3}\)) : 2 + \(\frac{1}{6}-\frac{1}{4}=\frac{7}{46}\)
(x + \(\frac{3}{12}-\frac{4}{12}\)) : 2 + \(\frac{2}{12}-\frac{3}{12}=\frac{7}{46}\)
(x - \(\frac{1}{12}\)) : 2 - \(\frac{1}{12}\)= \(\frac{7}{46}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{7}{46}+\frac{1}{12}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{42}{276}+\frac{23}{276}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{65}{276}\)
x - \(\frac{1}{12}=\frac{65}{276}.2\)
\(x-\frac{1}{12}=\frac{65}{138}\)
\(x=\frac{65}{138}+\frac{1}{12}\)
\(x=\frac{130}{276}+\frac{23}{276}\)
\(x=\frac{153}{276}=\frac{51}{92}\)
Ủng hộ mk nha !! ^_^