ab.101=ab.(100+1)
=ab00+ab
=abab
abc.7.11.13=abc.1001
=abc.(1000+1)
=abc000+abc
=abcabc
a )
ab . 101 = abab
b )
abc . 7 . 11 . 13 = abc . 1001 = abcabc
\(\overline{ab}\). 101 = \(\overline{abab}\)
\(\overline{abc}\). 7.11.13 = \(\overline{abc}\). 1001 = \(\overline{abcabc}\)
a, ab . 101 = ab(100 + 1)
= ab.100 + ab.1
= ab00 + ab
= abab
b, ab.7.11.13 = abc.1001
= abc(1000 + 1)
= abc.1000 + abc.1
= abc000 + abc
= abcab
ab . 101 abc . 7 . 11 . 13
= ab . ( 100 + 1) = abc . 1001
= ab . 100 + ab . 1 ( 1 số nhân 1 tổng ) = abc . ( 1000 + 1)
= ab00 + ab = abc . 1000 + abc . 1
= abab = abc00 + abc
= abcab
