(x+6)(x-3) =0
\(\left[{}\begin{matrix}x+6=0\\x-3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-6\\x=3\end{matrix}\right.\)
Kết luận \(x\in\) { -6; 3}
( x+6).(x-3)=0
⇔ x+6=0 hoặc x-3=0
⇔ x= -6 hoặc x=3
Vậy x ∈ { -6; 3 }
(x+6)(x-3) =0
\(\left[{}\begin{matrix}x+6=0\\x-3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-6\\x=3\end{matrix}\right.\)
Kết luận \(x\in\) { -6; 3}
( x+6).(x-3)=0
⇔ x+6=0 hoặc x-3=0
⇔ x= -6 hoặc x=3
Vậy x ∈ { -6; 3 }
( x + 5 ) ( x + 3 ) > 0
( x + 6 ) ( x - 5 ) <0
( 2x - 6 ) ( x + 5 ) < 0
1,x=3x2
2,(x+5)(x-3)-(x-30)=0
3,(2x-6)(x+4)+2(2x-6)=0
4,(2x-5)(x+9)+6x-15=0
3,(2x-5)(x+6)+8x-20=0
1.Tìm số nguyên x biết
|x-3|=|x+7|
|3x+2|+|x-8|
|x+3|+|y-8|=0
|x-5|+|x-3|=0
(x-2)(x+6)=0
x(3x+6)=0
(2x-4)(x3-1)=0
(x-2)(x+7)>0
(x+3)(x+5)>0
(x+2)(x-5)<0
Tìm x, biết:
a) (x - 8.25).4 = 0;
b) (x - 50): 4 - 3 = 97;
c) 8.(22 -x) = 8;
d) (x : 3-3)(x: 6-6) = 0.
Tìm x
(2x-7)+17=6
12-2.(3-3x)=-2
-14+3.(-x+5)=-20
-90:5.(-3-2x)=6
(x+1).(x-3)=0
(2x-2).(x+4)=0
(22+4).(x+3)=0
(5-x).(6-2x)=0
3.(x+1)+5=x+8
-4.(2x+9)-(-8x+3)-(x+13)=0
(-20.12).(x+3)=0
(2+x).(7+x)=0
104x.(6-x)=0
x^2-3x=0
|2x|-|x-14| 61 với >14
|6-x|.(-8)=-16
A=5.x^3.|x-1|+15 với x=2
B-(x-1)(x+2) với |x|=3
C=(3x-4)(x-6) với (x-1)(x+2)=0
Tìm biết: a) x (x - 6) = 0; b) x (x + 5) = 0; c) (x + 3)(x - 7) = 0; d) (x - 3) ( x 2 + 12) = 0
Tìm x thuộc Z biết: a) x ( x - 2) = 0 b) x ( x + 7 ) = 0 c) ( x + 6) ( x - 4) = 0; d) ( x - 3) ( 2 x 2 + 3) = 0
Tìm x
( x - 140) : 7 = 3^3 - 2^3 × 3
X - 6 :2 -( 48 -24 ) :2 :6 -3 = 0
X + 5×2 -( 32 + 16 ×3 :6 -15 ) =0
Bài 1: Tìm x
1/(2.x-5)+17=6
2/10-2.(4-3x)=-4
3/-12+3.(-x+7)=-18
4/24:(3.x-2)=-3
5/-45:5.(-3-2.x)=3
6/x.(x+7)=0
7/(x+12).(x-3)=0
8/(-x+5).(3-x)=0
9/x.(2+x).(7-x)=0
10/(x-1).(x+2).(-x-3)=0