\(\dfrac{x}{60}+\dfrac{1}{20}+\dfrac{x+2}{60}=\dfrac{x}{120}\)
=>\(\dfrac{x+3+x+2}{60}=\dfrac{x}{120}\)
=>\(\dfrac{2x+5}{6}=\dfrac{x}{12}\)
=>\(2x+5=\dfrac{x}{2}\)
=>4x+10=x
=>3x=-10
=>\(x=-\dfrac{10}{3}\)
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