15)=0
x + 10 - ( 32 + 48 :6 - 15 ) = 0
x + 10 - ( 32 + 8 - 15 ) =0
x + 10 - 25 = 0
x + -15 = 0
x = 0 - -15
x = 15
`x+5.2-(32+16.3:6-15)=0`
`x+5.2-(32+48:6-15)=0`
`x+5.2-(32+8-15)=0`
`x+5.2-(40-15)=0`
`x+5.2-25=0`
`x+10-25=0`
`x+(-15)=0`
`x-15=0`
`x=0+15`
`x=15`
Vậy `x=15`