`||x+5|-4|=3`
`@TH1:|x+5|-4=3`
`=>|x+5|=7`
`=>` $\left[\begin{matrix} x+5=7\\ x+5=-7\end{matrix}\right.$
`=>` $\left[\begin{matrix} x=2\\ x=-12\end{matrix}\right.$
`@TH2:|x+5|-4=-3`
`=>|x+5|=1`
`=>` $\left[\begin{matrix} x+5=1\\ x+5=-1\end{matrix}\right.$
`=>` $\left[\begin{matrix} x=-4\\ x=-6\end{matrix}\right.$
Vậy `x in {-12;-6;-1;2}`
Tìm X:
a, 3/7- (2/5 + X + 3/2) = 5/14 - /4/35 - (-11)/70 /
b,3/4(x-8) = 5/7.(4-1/2)
c,3/2 - 4(1/4 - x) = 2/3 - 7x
d,4.(1/2-x) - 5.(x-3/10) = 7/4
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
Tìm x nguyên sao cho:
a) 5*3^x+6 = 2*3^5 + 3*3^5
b) 5^x+4-3*5^x+3=2*5^4
Tính giá trị các biểu thức sau và viết kết quả dưới dạng bình phương của 1 số
A = 2^5 x (-5)^2 - 8^2 - 7
B = 2^3 x (-4)^2 + (-3)^2 x 3^2 - 40
C= (1/4 - 1/2 - 1) ^3 x (2 - 2/5)^3
D = ( -1/4)^2 : (1/2 - 1/3)
E= 4 x (1/4)^2 + 25 x [(3/4)^3 : (5/4)^3] : (3/2)^3
F = 2^3 + 3 x (1/2)^0 - 1+[(-2)^2 : 1/2] - 8
X-3/8=1/6-1/5
-7/10(x+1/3) =4/5
X-4/3=5/6
( -1/2)-3/5=4/6
6/5+(x-2/3)=4/7
1, |x+1|+|x-2|+|x+3|=6
2, 2.|x+2|+|4-x|=11
3, |x-2|+|x-5|=3
4, |x-3|+|x+5|=8
5, |2x-1|+|2x-5|=4
Tìm x a) |5/3.x|=|-1/6|
B) |3/4.x-3/4|-3/4=|-3/4|
C)|x+3/5|-|x-7/3|=0
Tìm x biết \(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^4}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)=2\(2^x\)
Tìm x, biết:a,x/4/2=4/x/2;b,x^4=y^4;x^5=y^5;(x+5)^3=-64;e,(2x-3)^2=9
Tìm x, biết
a)\(\dfrac{1}{2}\)x\(x\)-\(\dfrac{7}{3}\)=\(\dfrac{-5}{6}\)+\(\dfrac{3}{4}\)x\(x\)
b)\(\dfrac{4}{5}\)x\(x\)-\(\dfrac{6}{5}\)=\(\dfrac{1}{2}\)+\(\dfrac{3}{2}\)x\(x\)
c)\(\dfrac{2}{5}\)x(3x\(x\)+\(\dfrac{3}{4}\))=\(1\dfrac{1}{5}\)-\(\dfrac{1}{3}\)x\(x\)
d)2x(3x\(x \)+\(\dfrac{3}{4}\))+\(\dfrac{4}{5}\)=\(\dfrac{1}{2}\)-2x\(x\)
