X^4+x^2-20=0<=>x^4-4x^2+5x^2-20=0<=>x^2(x^2-4)+5(x^2-4)=0<=>(x^2+4)(x^2+5)<=>(x-2)(x+2)(x^2+5)<=>X=2;X=-2
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17 tháng 12 2023 lúc 21:31
Tìm x: \(-x^4+4x^2-5x^2+20=0\)
5x - 20 - (x-4)^2 = 0(tìm x)
a; 6(x-3)(x-4)-6x(x-2)=4
b; (2x-1)-(x+1)^2=0
c; (x+2)(x+3)-(x-2)(x+5)=6
d; x^2-x+1=0
e; 4x^2+y^2-20-2y+26=0
Tìm x biết:a)
x
6
+ 2
x
3
+1 0; b) x(x - 5) 4x - 20;c)
x
4
-2
x
2
8-4
x
2
; d) (
x
3
-
x
2
) - 4
x
2
+ 8x-4 0.
Đọc tiếp
Tìm x biết:
a) x 6 + 2 x 3 +1 = 0; b) x(x - 5) = 4x - 20;
c) x 4 -2 x 2 =8-4 x 2 ; d) ( x 3 - x 2 ) - 4 x 2 + 8x-4 = 0.
1) x(x-5)-4x+20=0
2) 3(x+1)+x(x+1)
3) 2x^3+x=0
4) x^3-16x=0
5) x^2+6x=-9
6) x^4-2x^3+10x^2-20x=0
7) (2x-3)^2=(x+5)^2
x^4=20-10x^2-x=0
1) 2x+6=0
2)(x^2-2x+1)-4=0
3)x-2/x+2+3/x-2=x^2-11/x^2-4
4)x(x^2-1)=0
5)4x+20=0
6)x+3/x+1+x-2/x=2
7)1+2x-5/6=3-x/4
8x+2/x-2-1/x=2/x^2-2x
9)2(x+1)=5x-7
Tìm x:
1, x(x-20)+x-2=0
2, 5x(x-3)-x+3=0
3, 3x(x-5)-(x-1)(2+3x)=30
4, (x+2)(x+3)-(x-2)(x+5)=0
giải các phương trình sau:
1)4+2x.(2x+4)=-x
2)(2x-3)^2=2x-3
3)x^2-9x+20=0
4)x^2-1+2.(x+1)=0
5)16x^2-8x+1=4.(x+3).(4x-1)
6)27x^2.(x+3)-12.(x^2+3x)=0