Question

x^4+2x^3-x^2-4x-2

Answer 1

Mình coi như đây là phân tích đa thức thành nhân tử nha

\(x^4+2x^3-x^2-4x-2\\ =\left(x^4+x^3\right)+\left(x^3+x^2\right)-\left(2x^2+2x\right)-\left(2x+2\right)\\ =x^3\left(x+1\right)+x^2\left(x+1\right)-2x\left(x+1\right)-2\left(x+1\right)\\ =\left(x^3+x^2-2x-2\right)\left(x+1\right)\\ =\left[x^2\left(x+1\right)-2\left(x+1\right)\right]\left(x+1\right)\\ =\left(x^2-2\right)\left(x+1\right)^2\)