x³ + 2x = 0
x(x² + 2) = 0
x = 0 hoặc x² + 2 = 0
*) x² + 2 = 0
x² = -2 (vô lí)
Vậy x = 0
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8x(x - 2017) - 2x + 4034) = 0
8x(x - 2017) - 2(x - 2017) = 0
(x - 2017)(8x - 2) = 0
x - 2017 = 0 hoặc 8x - 2 = 0
*) x - 2017 = 0
x = 2017
*) 8x - 2 = 0
8x = 2
x = 1/4
Vậy x = 1/4; x = 2017
1)x^3+2x=0
<=>x(x^2+2)=0
<=>x^2=-2(vô lý)
2)8x(x-2017)-2x+4034=0
<=>(x-2017)(8x-2)=0
<=>X=2017,x=1/4