=>x^2+6x+9+(4-x)(4+x)=1
=>x^2+6x+8+16-x^2=0
=>6x+24=0
=>x+4=0
=>x=-4
(x2+2.x3+32) + (4- x) (4+ x)=1
x2+ 6x + 9 + 16 - x2=1
6x = 1 - 9 -16
6x = -24
x =-4
=>x^2+6x+9+(4-x)(4+x)=1
=>x^2+6x+8+16-x^2=0
=>6x+24=0
=>x+4=0
=>x=-4
(x2+2.x3+32) + (4- x) (4+ x)=1
x2+ 6x + 9 + 16 - x2=1
6x = 1 - 9 -16
6x = -24
x =-4
Cho x>=0,y,z<=2,x+y+z=3.tim min,max x^4+y^4+z^4+12(1-x)(1-y)(1-z)
1 Tim x
I x2 - 5x + 4 I = x + 4
2 Tim Min
\(A=\left(x-1\right)^4+\left(x-3\right)^4+6\left(x-1\right)^2\left(x-3\right)^2\)
3 Cho \(x^2-3y^2+2xy-2x+10y+4=0\)
a Tìm nguyêm của phương trình thỏa mãn \(x^2+y^2=10\)
b Tìm nguyem nguyên của phương trình
tim x nguyen thoa man
x14+x24+x34+...+x74=2008
Tim Gia Tri Nho Nhat Cua
a) A = x - 4 can x + 9
b) B = x - 3 can x - 10
c ) C = x - can x + 1
d ) D = x + can x + 2
P=\(\frac{3\left(x+\sqrt{x}-3\right)}{x+\sqrt{x}-2}+\frac{\sqrt{x}+3}{\sqrt{x}+2}+\frac{\sqrt{x}-2}{1-\sqrt{x}}\\ \)
a, rut gon
b, tim x de P<\(\frac{15}{4}\)
c, tim gia tri lon nhat cua P
tim x (x+3)(2x-1)-(x-4)(2x+1)=10
1) Tim GTNN (x > 0) B = \(5x+\frac{1}{x^3}\)
2) Rút gọn biểu thức A = \(\sqrt{x+4\sqrt{x-4}}+\sqrt{x-4\sqrt{x-4}}\)
1.Giải`phương trình:\(x^2-10x+27=\sqrt{6-x}+\sqrt{x-2},\)
2.Tim GTLN,GTNN cua \(A=\frac{x+1}{x^2+x+1}\)
3.Tim m de 3 duong thang dong quy :
\(d_1:y=x-4;d_2:y=2x-1;d_3:y=mx+2\)
tim min y= (x^4+x^2+5)/(x^4+2x+1)