\(\frac{x+3}{x+5}=\frac{3}{5}\)
=> (x + 3).5 = 3.(x + 5)
=> 5x + 15 = 3x + 15
=> 5x - 3x = 15 - 15
=> 2x = 0
=> x = 0 : 2 = 0
Vậy x = 0
\(\frac{x+3}{x+5}=\frac{3}{5}\)
<=> (x + 3).5 = (x + 5).3
<=> 5x + 15 = 3x + 15
<=> 5x + 15 - 15 = 3x + 15 - 15
<=> 5x = 3x
<=> 5x - 3x = 3x - 3x
<=> 2x = 0
<=> x = 0 : 2
=> x = 0
\(\frac{x+3}{x+5}=\frac{3}{5}\).Tim x.Giup mik.
Mik viet the nay cho cac bn de nhin.Thank^_^
\(\frac{x+3}{x+5}=\frac{3}{5}\)
\(\Leftrightarrow\frac{5\left(x+3\right)}{5\left(x+5\right)}=\frac{3\left(x+5\right)}{5\left(x+5\right)}\)
\(\Leftrightarrow5\left(x+3\right)=3\left(x+5\right)\)
\(\Leftrightarrow5x+15=3x+15\)
\(\Leftrightarrow2x=0\)
\(\Leftrightarrow x=0\)
