\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{1}{2}\\\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{1}{2}\\\left(x-4\right)\left(3x+2\right)=0\end{matrix}\right.\Leftrightarrow x=4\)