\(x^2+x=0\)
\(\Rightarrow x\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
Vậy: \(S=\left\{0;-1\right\}\)
x2 + x = 0
=) x(x + 1) = 0
=) x = 0 hoặc x + 1 = 0
=) x = 0 hoặc x = -1.
=) x ∈ { 0;-1}