\(\dfrac{x^2+6x+9}{2x+6}\left(x\ne3\right)=\dfrac{\left(x+3\right)^2}{2\left(x+3\right)}=\dfrac{x+3}{2}\)
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P)(9-x)(x^2+2x-3) n)(-x+3)(x^2+x+1) O)(-6x+1/2)(x^2-4x+2) q)(6x+1)(x^2-2x-3) r)(2x+1)(-x^2-3x+1) U)(2x-3)(-x^2+x+6) s)(-4x+5)(x^2+3x-2) V)(-1/2x+3)(2x+6-4x^3)
a)4/x+2+2/x-2+5x-6/4-x2 ; b)1-3x/2x+3x-2/2x-1+3x-2/2x-4x2 ; c)1/x2+6x+9+1/6x-x2-9+x/x2-9
Tìm đkxđ của: 1, 3x/ 4x-8 2, 2x/ x²-9 3, 6/x³+1 4, 6x²/x²-2x+1 5, x-2/x²+3 6, 2x/x²+3+2
(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
tìm x: (3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
Tìm x, biết: (3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
\(\frac{x^2+9}{2x+6}+\frac{6x}{2x-6}\)
(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)