\(x+\dfrac{2}{3}=\dfrac{9}{11}\Rightarrow x=\dfrac{9}{11}-\dfrac{2}{3}=\dfrac{5}{33}\\ x-\dfrac{3}{10}=\dfrac{4}{15}\Rightarrow x=\dfrac{4}{15}+\dfrac{3}{10}=\dfrac{17}{30}\\ x\times\dfrac{1}{7}=\dfrac{5}{6}\Rightarrow x=\dfrac{5}{6}:\dfrac{1}{7}=\dfrac{35}{6}\\ x:\dfrac{3}{5}=\dfrac{1}{6}\Rightarrow x=\dfrac{1}{6}\times\dfrac{3}{5}=\dfrac{1}{10}\)