(x^2 + 2x)^2 - 9x^2 - 18x + 20 = (x^2 + 2x)^2 - 9(x^2 + 2x) + 20
Đặt x^2 + 2x = a ta có:
a^2 - 9a + 20 = (a - 4)(a - 5)
Thay ngược lại ta có: (x^2 + 2x - 4)(x^2 + 2x - 5)
e) (x2+2x)2+9x2+18x+20=(x2+2x+4)(x2+2x+5)(x2+2x)2+9x2+18x+20=(x2+2x+4)(x2+2x+5)
\(=\left(x^2+2x\right)^2+9\left(x^2+2x\right)+20\)
\(=\left(x^2+2x+5\right)\left(x^2+2x+4\right)\)