Ta có : \(x^2-4x+4+y^2=0\)
\(\Leftrightarrow\left(x-2\right)^2+y^2=0\)
Thấy : \(\left\{{}\begin{matrix}\left(x-2\right)^2\ge0\\y^2\ge0\end{matrix}\right.\)
\(\Rightarrow\left(x-2\right)^2+y^2\ge0\)
- Dấu " = " xảy ra \(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\y=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\y=0\end{matrix}\right.\)