a/ x=3
y= 4
b/ x= -8
y= 10
c/ x= 7
y= -10
tích mk nha mọi người...^.^...♥
1)[ x+2 ] . [ y - 3 ] = 5
<=>xy2y-3x-6=5
=>xy+2y-3x-11=0
=>(x+2)y-3x-11=0
=>\(y=\frac{3+11}{x+2}\)
2)[ x+3 ] . [ y - 5 ] = -25
<=>(x+3)y-5x-15=-25
=>(x+3)y-5x-(-25)-15=0
=>(x+3)y-5x+10=0
=>x+3=0
=>x=-3
<=>(x-4)y+x-4=-27
=>(x-4)y+x-(-27)-4=0
=>(x-4)y+x+23=0
=>x-4=0
=>x=4
=>y+1=0
=>y=-1
vậy x=4 ; y=-1