Question

(x+1).(y+2)=5

 

Answer 1

\(\left(x+1\right).\left(y+2\right)=5\)

\(\Leftrightarrow\orbr{\begin{cases}x+1=5\\y+2=5\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=4\\y=3\end{cases}}\)

Vậy \(\left(x;y\right)\in\left(4;3\right)\)

Answer 2

\(\left(x+1\right)y+2=5\)

\(\left(x+1\right)+2x-5+2=0\)

\(\left(x+1\right)y+2x+3=0\)

\(x+1=0\Rightarrow x=-1\)

\(y+2=0\Rightarrow y=-2\)

Answer 3

( x + 1 ) ( y + 2 ) = 5 

  x + 1 = 5

  y + 2 = 5

  x = 5 - 1 = 4

  y = 5 - 2 = 3

  x = 4 ; y = 3