Question

(x+1)(x²+x+1)(x-1)(x²-x+1)

Tính

Answer 1

\(=\left[\left(x-1\right)\left(x^2+x+1\right)\right]\left[\left(x+1\right)\left(x^2-x+1\right)\right]\\ =\left(x^3-1\right)\left(x^3+1\right)\\ =x^6-1\)

Answer 2

(x+1)(x²+x+1)(x-1)(x²-x+1)
\(\left(x+1\right)\left(x^2-x+1\right)\left(x-1\right)\left(x^2+x+1\right)=\left(x^3+1\right)\left(x^3-1\right)=\left(x^3\right)^2-1=x^6-1\)