(x+1).(2x+1)=288
(x+1).(2x+1)=288 tìm x , ae giúp v
tìm x biết
a/\(2^x+2^{x+3}=288\)
b/\(\left(2x-1\right)^3=-27\)
A, (2367-x) - (210- 7) = 152 - 20
B, 8.6+288: (x-3)2 = 50
C, ( x+1)+(+2)+(+3)+....+(x+100)=5750
D, 10+2x=45: 43
1;Tính
235-288:[4×(48-72)]
2;Tìmx
2x+12-3x=-21
6^2.2^2.x-1=288 tìm x
B1:Tính
a,3.52-16:22
b,22.17-23.14
c,15.141+59.10
d,17.85+15.17-120
e,100-[75-(7-2)]2
g,(23.94+93.45):(92.10-92)
B2:Tìm x
a,420+65.4=(x+175):3+30
b,96-3.(x+1)=42
c,(x-47)-115=0
d,(x-36):18=12
e,2x=16
B3:Tìm x
a,60-3.(x-2)=51
b,4x-20=25:22
c,8.6+288:(x-3)2=50
mk đang càn rất gấp
3 . 2 mũ x + 2 mũ x +1 + 2 mũ x+2 = 288
Tìm x biết 5×2x+1 - 2x = 288