Question

(x+1) + (x+3) + (x+5)+ .... + (x+99) =0

 

Answer 1

\(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+99\right)=0\\ \left(x+x+...+x\right)+\left(1+3+5+...+99\right)=0\\ 50x+2500=0\\ x=-50\)

Vậy x = -50

Answer 2

Ta có: \(\left(x+1\right)+\left(x+3\right)+...+\left(x+99\right)=0\)

\(\Leftrightarrow50x=-2500\)

hay x=-50