\(\frac{x+1}{3}=\frac{x-5}{2}\)
<=> 2.(x + 1) = 3.(x - 5)
<=> 2x + 2 = 3x - 15
<=> 2x - 3x = -15 - 2
<=> -x = -17
<=> x = 17
Ta có:
\(\frac{x+1}{3}\)=\(\frac{x-5}{2}\)
=> 2( x + 1 ) = 3(x-5)
=> 2x + 2 = 3x - 15
=> 2 + 15 = 3x - 2x
=> 17 = x
Vay x = 17
Duyet nha
\(\frac{x+1}{3}=\frac{x-5}{2}\)
=>2(x+1)=3(x-5)
2x+2 =3x-15
2+15 =3x-2x
17 =x
vậy x=17