\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)ĐKXĐ: \(x\ne-\frac{1}{2};x\ne-3\)
\(\Rightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)
\(\Leftrightarrow x^2+x+3x+3=x^2+0,5x+4x+2\)
\(\Leftrightarrow x^2+4x+3=x^2+4,5x+2\)
\(\Leftrightarrow x^2-x^2+4x-4,5x=2-3\)
\(\Leftrightarrow-0,5x=-1\)
\(\Leftrightarrow x=2\)
vậy x=2