\(\left(x+7\right)^{10}.\left(x+2\right)^2=5^0.7^0\)
\(\Rightarrow\left(x+7\right)^{10}.\left(x+2\right)^2=1.1=1\)
mà \(\left\{{}\begin{matrix}\left(x+7\right)^{10}\ge0,\forall x\\\left(x+2\right)^2\ge0,\forall x\end{matrix}\right.\)
\(\Rightarrow\left(x+7\right)^{10};\left(x+2\right)^2\in\left\{1\right\}\left(x\inℕ\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x+7\right)^{10}=1\\\left(x+2\right)^2=1\end{matrix}\right.\) (Vô lý)
\(\Rightarrow x\in\varnothing\)
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