\(\Rightarrow\left(x-7\right)\left(x^2-x+6\right)-x\left(x-7\right)=0\)
\(\Rightarrow\left(x-7\right)\left(x^2-2x+6\right)=0\)
\(\Rightarrow x=7\left(do.x^2-2x+6=\left(x-1\right)^2+5\ge5>0\right)\)
\(\Rightarrow\left(x-7\right)\left(x^2-x+6\right)-x\left(x-7\right)=0\)
\(\Rightarrow\left(x-7\right)\left(x^2-2x+6\right)=0\)
\(\Rightarrow x=7\left(do.x^2-2x+6=\left(x-1\right)^2+5\ge5>0\right)\)
4. x^2 − 5x + 6
5. x^2+7x+10
6. x + 7√x + 10
7. 3x^4 + 7x^2 + 4
8. x^2-x-2
9. x^6 − x^3 − 2
a) 6-7x+7=-8x+12
b) \(\dfrac{\text{4x-1}}{8}\)\(\)=\(\dfrac{6-x}{2}\)-\(\dfrac{1}{4}\)
c) 2x(x-3)+7x-21+0
d) \(\dfrac{x}{x-3}\)+\(\dfrac{x-2}{x+3}\)\(\dfrac{2\left(x^2+6\right)}{x^2-9}\)
Giúp mik với
Tìm x biết
(x-7)(x^2+x+6)=x^2-7x
a,4x-10=0 b, 7-3x=9-x c, 2x-(3-5x) = 4(x+3)
d, 5-(6-x)=4(3-2x) e, 4(x+3)=-7x+17 f, 5(x-3) - 4=2(x-1)+7
g, 5(x-3)-4=2(x-1)+7 h,4(3x-2)-3(x-4)=7x+20
câu 6: (x-5)(x-4)=10-2x
câu 7:(x ²+1)(x-2)+2x=4
câu 8:(x+3)(x ²-3x+9)=7x ³+21x
1) (x^2+x)^2-2(x^2+x)-15
2) (x^2+2x)^2+9x^2+18x+20
3) (x^2+3x+1)(x^2+3x+2)-6
4) x^2+2xy+y^2-x-y-12
5) x^2-16-4xy+4y^2
6) x^4 -3x^3-x+3
7) x^2-10x+16
8) 2x^2+7x+3
9) 3x^2+7x+2
10) 2x^2+5x-3
1.\(\left(x-5\right)^2+3\left(x-5\right)=0\)
\(2,\dfrac{2x-1}{3}-\dfrac{5x+2}{7}=x+13\)
\(3,\dfrac{x-1}{x+2}-\dfrac{x}{x-2}=\dfrac{7x-6}{4-x^2}\)
a) (X-2)(x+3)-3(4x-2)=(x-4)\(^{^{ }2}\)
b) \(\dfrac{2x^2+1}{8}-\dfrac{7x-2}{12}=\dfrac{x^2-1}{4}-\dfrac{x-3}{6}\)
c) \(x-\dfrac{2x-2}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)
d) \(\left(2x+5\right)^2=\left(x+2\right)^2\)
e) \(x^2-5+6=0\)
g) \(2x^3+6x^2=x^2+3x\)
h) \(\left(x+\dfrac{1}{2}\right)^2+2\left(x+\dfrac{1}{x}\right)-8=0\)
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