Question

(x +5) (3x – 7)=0

Answer 1

\(\left(x+5\right)\left(3x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+5=0\\3x-7=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{7}{3}\end{matrix}\right.\)

Answer 2

\(\left(x+5\right)\left(3x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+5=0\\3x-7=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{7}{3}\end{matrix}\right.\)

Vậy \(x\in\left\{-5;\dfrac{7}{3}\right\}\)

Answer 3

x=-5

x=7/3

Answer 4

(x +5) (3x – 7)=0

\(=>\left[{}\begin{matrix}x+5=0\\3x-7=0\end{matrix}\right.=>\left[{}\begin{matrix}x=-5\\x=\dfrac{7}{3}\end{matrix}\right.\)

Vậy....

Answer 5

(x + 5)(3x - 7) = 0

⇔ x + 5 = 0 hoặc 3x - 7 = 0

⇔ x = 0 - 5 hoặc 3x = 7

⇔ x = -5 hoặc x = \(\dfrac{7}{3}\)

Vậy tập nghiệm S = { -5; \(\dfrac{7}{3}\)}

Answer 6

=> x + 5 = 0 hoặc 3x - 7 = 0

TH1:

x + 5 = 0

=> x = -5

TH2:

3x - 7 = 0

=> 3x = 7

=> x = 7/3

Vậy x = -5 hoặc x = 7/3

Answer 7

\(x=-5\)

\(x=\dfrac{7}{3}\)