Các câu hỏi tương tự
giải pt :
√x^2 -4x +6 = x+4
√(x^2 -3x +2 ) -3 -x =0
√ 5x-1 -√3x-2 -√x-1 = 0
√x+1 + √x+10 = √x+6 +√x+5
√x+1 + √5x =√4x-3 + √2x+4
1) √(2x-1) <= 8-2x
2) √[(x+1)(4-x)] > x-2
3) √(x-2x^2+1) > 1-x
4) √(x+5) - √(x+4) > √(x+3)
5) √(5x-1) - √(x-1) > √(2x-4)
6) √(x+3) >= √(2x-8) + √(7-x)
7) √(x+2) - √(3-x) < √(5-2x)
8) √(x+1) > 3 - √(x+4)
9) √(5x-1) - √(4x-1)<= 3√x
10) { {√[2(x^2-16)]} / √(x-3) }+ √(x-3) > (7-x) / √(x-3)
Giúp mình 10 câu này với ạaa
(x^2-5x+1)(x^2-4)=6(x-1)^2
\(x^2-5x+14-4\sqrt{x+1}=0\Leftrightarrow(x^2-4x+4)-(x+1-2.2.\sqrt{x+1}+4)+6=0\Leftrightarrow(x-2)^2-(\sqrt{x+1}-2)^2+6=0\Leftrightarrow tính\)
(1) giải pt quy về ax^2+bx+c01) x^23x 2) x^2-3x4 3) x^4-5x^2+60 4) x^39x5) left(x+2right)left(x-3right)x^2-4 6) dfrac{x+11}{x^2-1}-dfrac{x-1}{x+1}dfrac{2left(x+7right)}{x+1}giúp mk vs mk cần gấp
Đọc tiếp
(1) giải pt quy về \(ax^2+bx+c=0\)
1) \(x^2=3x\) 2) \(x^2-3x=4\)
3) \(x^4-5x^2+6=0\) 4) \(x^3=9x\)
5) \(\left(x+2\right)\left(x-3\right)=x^2-4\) 6) \(\dfrac{x+11}{x^2-1}-\dfrac{x-1}{x+1}=\dfrac{2\left(x+7\right)}{x+1}\)
giúp mk vs mk cần gấp
1\(\sqrt{5+2\sqrt{8}}-\sqrt{5-2\sqrt{8}}\) 2)\(\dfrac{\sqrt{x^2+2\sqrt{3x}+3}}{x^2-3}\) 3) \(\dfrac{\sqrt{x^2-5x+6}}{\sqrt{x-2}}\) 4)\(\dfrac{\sqrt{\left(x-4\right)^2}}{x^2-5x+4}\) 5) \(\dfrac{3x+1}{\sqrt{9x^2+6x+1}}\)
p(x),q(x) là số vô tỉ hay hữu tỉ:
P(x)=\(x^6+2x^5-2x^4+x^3+5x^2-6x-1\)
Q(x)=\(x^7-2x^6+2x^5-x^4-5x^3-6x^2-6x+1\)
giải pt
a 4(x+3)^2=(2x+6)^2
b (3x+4)^2=4(x+3)
c (6x+3)^2=(x-4)^2
d (x^2+3x+2)(x^2+3x+3)-2=0
e(x^2-5x)+10(x^2-5x)+24=0
f(x^2+x+1)(x^2+x+2)=12
gx(x+1)(x-1)(x+2)=24
h(x+1)(x+2)(x+3)(x+4)-24=0
lm giúp mik nha các bn
20 tháng 8 2021 lúc 14:43
giải phương trình sau:
a) \(4x^2+\left(8x-4\right).\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
b) \(8x^3-36x^2+\left(1-3x\right)\sqrt{3x-2}-3\sqrt{3x-2}+63x-32=0\)
c) \(2\sqrt[3]{3x-2}-3\sqrt{6-5x}+16=0\)
d) \(\sqrt[3]{x+6}-2\sqrt{x-1}=4-x^2\)