\(x-3=2x+4\)
\(x-2x=3+4\)
\(-1x=7\)
\(x=\frac{7}{-1}\)
\(x=-7\)
\(x-3=2x+4\)
\(\Rightarrow x-2x=4+3\)
\(x.\left(1-2\right)=7\)
\(x.\left(-1\right)=7\)
\(x=-7\)
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Ta có :
\(x-3=2x+4\)
\(\Leftrightarrow\)\(2x-x=-3-4\)
\(\Leftrightarrow\)\(x=-7\)
Vậy \(x=-7\)
\(x-3=2x+4\)
\(\Leftrightarrow\)\(x-2x=3+4\)
\(\Leftrightarrow\)\(-x=7\)
\(\Leftrightarrow\)\(x=-7\)
Vậy...
x - 3 = 2x + 4
x - 2x = 4 + 3
- 1x = 7
x = 7 : ( -1 )
x = - 7