a)\(\left(x-2\right)^2=1\)
\(\Rightarrow\left(x-2\right)^2=\orbr{\begin{cases}1^2\\\left(-1\right)^2\end{cases}}\)
\(\Rightarrow x=\orbr{\begin{cases}3\\1\end{cases}}\)
b)\(\left(2x-1\right)^3=-27\)
\(\left(2x-1\right)^3=\left(-3\right)^3\)
\(\Rightarrow2x-1=-3\)
\(\Rightarrow x=-1\)
c)\(\frac{3}{2}:\left(x-\frac{5}{3}-\frac{17}{3}\right)=\frac{11}{13}\)
\(\Rightarrow\frac{3}{2}:\left(x-\frac{22}{3}\right)=\frac{11}{13}\)
\(\Rightarrow\frac{3}{2x}-11=\frac{11}{13}\)
\(\frac{3}{2x}=\frac{11}{13}+\frac{39}{13}=\frac{50}{13}\)
\(\Rightarrow39=100x\)
\(\Rightarrow x=\frac{39}{100}\)
a. (x-2)2 = 1
(x-2)2 = 12
x-2 = 1
x = 1+2
x = 3
b. (2x-1)3 = -27
(2x-1)3 = (-3)3
2x-1 = -3
2x = -3 + 1
x = -2:2
x = -1
c. \(\frac{3}{2}:\left(x-\frac{5}{3}-\frac{17}{3}\right)=\frac{11}{3}\)
\(x-\frac{5}{3}-\frac{17}{3}=\frac{3}{2}:\frac{11}{3}\)
\(x-\frac{5}{3}=\frac{9}{22}+\frac{17}{3}\)
\(x=\frac{406}{66}+\frac{5}{3}\)
\(x=\frac{511}{66}\)
mk làm lại câu a nha
a. (x-2)2 = 1
(x-2)2 = \(\orbr{\begin{cases}1^2\\\left(-1\right)^2\end{cases}}\)
x = \(\orbr{\begin{cases}3\\1\end{cases}}\)