Ta có: \(\dfrac{x-2}{5}=\dfrac{x+1}{6}\)
\(\Leftrightarrow6\left(x-2\right)=5\left(x+1\right)\)
\(\Leftrightarrow6x-12=5x+5\)
\(\Leftrightarrow6x-5x=5+12\)
hay x=17
Vậy: x=17
x-\(\dfrac{ }{ }\)2/5=x+1/6
➩\(\dfrac{x-2}{5}\)=\(\dfrac{x+1}{6}\)
➩(x-2).6=5(x+1)
➩6x-12=5x+5
➩6x-5x=5+12
➩x=17
Vậy x=17