\(x:25\%+x:0,5+x\cdot5=270\)
\(x\cdot4+x\cdot2+x\cdot5=270\)
\(x\cdot\left(4+2+5\right)=270\)
\(x\cdot11=270\)
\(x=\dfrac{270}{11}\)
X : 25% + X : 0,5 + X x 5 - X = 270
X : \(\dfrac{1}{4}\) + X : \(\dfrac{1}{2}\) + X x 5 -X =270
X x 4 +X x 2 +X x 5 -X = 270
X x ( 4+ 2+ 5 -1 ) = 270
x x 10 = 270
X = 270 : 10
X = 27
X x 4 + X x 2 +X x 5 - X= 270
X x (4+2+5)-x =270
X x 11- X x1= 270
X x (11-1) =270
X x10=270
X=270 :10
X=27