Question

(X-2)(3+X )>0

Answer 1

`(x-2)(3+x)>0`

`<=>` \(\left[ \begin{array}{l}\begin{cases}x-2>0\\x+3>0\\\end{cases}\\\begin{cases}x-2<0\\x+3<0\\\end{cases}\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}\begin{cases}x>2\\x>-3\\\end{cases}\\\begin{cases}x<2\\x<-3\\\end{cases}\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x>2\\x<-3\end{array} \right.\) 

Answer 2

TH1: \(\left\{{}\begin{matrix}x-2>0\\x+3>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>2\\x>-3\end{matrix}\right.\Leftrightarrow x>2\)

TH2: \(\left\{{}\begin{matrix}x-2< 0\\x+3< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< 2\\x< -3\end{matrix}\right.\Leftrightarrow x< -3\)

Vậy `x>2` hoặc `x<-3`.