\(x\div\dfrac{2}{3}+\dfrac{4}{5}=\dfrac{8}{7}\times\dfrac{7}{10}\)
\(x\div\dfrac{2}{3}+\dfrac{4}{5}=\dfrac{4}{5}\)
\(x\div\dfrac{2}{3}=0\)
\(x=0\)
\(x\div\dfrac{2}{3}+\dfrac{4}{5}=\dfrac{8}{7}\cdot\dfrac{7}{10}\)
\(x\cdot\dfrac{3}{2}+\dfrac{4}{5}=\dfrac{4}{5}\)
\(x\cdot\dfrac{3}{2}=\dfrac{4}{5}-\dfrac{4}{5}=0\)
\(x=0\div\dfrac{3}{2}=0\)
Vậy x = 0
\(x\cdot\dfrac{3}{2}+\dfrac{4}{5}=\dfrac{8}{7}\cdot\dfrac{7}{10}\)
\(\dfrac{3}{2}x+\dfrac{4}{5}=\dfrac{4\cdot2\cdot7}{7\cdot2\cdot5}=\dfrac{4}{5}\)
\(\dfrac{3}{2}x=\dfrac{4}{5}-\dfrac{4}{5}=0\)
\(\Rightarrow x=0\)
