(x-2).(2x+3).(5-3x)=0
=> x - 2 = 0 => x = 2
2x + 3 = 0 => 2x = -3 => x = -1,5
5 - 3x = 0 => 3x = 5 => x = \(\frac{5}{3}\)
t i c k nha!! 756875787768976969578567547635765774574578
(x-2).(2x+3).(5-3x)=0
TH1:
x-2 =0 => x=2
TH2:
2x +3 = 0 => 2x =-3 => x= -3/2
TH3:
5-3x =0 => 3x= 5 => x= 5/3
Vậy x=2; -3/2 ; 5/3
(x-2).(2x+3).(5-3x)=0
\(\Rightarrow\hept{\begin{cases}x-2=0\\2x+3=0\\5-3x=0\end{cases}\Rightarrow\hept{\begin{cases}x=2\\2x=3\\3x=5\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=\frac{3}{2}\\x=\frac{5}{3}\end{cases}}}\)
Vậy \(x=2;\frac{3}{2};\frac{5}{3}\)