<=>(x-1)(x2+x+1)-2=(x+1)(x2-x-1)
=>x(x-1)(x+1)=(x-1)x(x+1)
<=>(x+1)(x2-x-1)=(x-1)x(x+1)
<=>x+1=0
=>x=0-1
=>x=-1
vay pt tren co nghiem x=-1
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Giải pt : a) 2/-x2+6x-8 - x-1/x-2 = x+3/x-4
b) 2/x3-x2-x+1 = 3/1-x2 - 1/x+1
c) x+2/x-2 - 2/x2-2x = 1/x
d) 5/-x2+5x-6 + x+3/2-x = 0
e) x/2x+2 - 2x/x2-2x-3 = x/6-2x
f) 1/x-1 - 3x2/x3-1 = 2x/x2+x-1
Rút gọn biểu thức:
a) (x + 2)(x – 2) – (x + 1)2
b) (2x – 1)(4x2 + 2x + 1) – (2x + 1)( 4x2 – 2x + 1)
3. Tìm x biết:
a) (x + 2)(x2 – 2x + 4) – x(x2 – 2) = 15
b) (x – 1)3 – x(x2 – 3x – 4) = 13
thanks
rút gọn
(x + 1) (x2 - x + 1) - (x -1) (x2 + x + 1)
(2x + 3) (2x-3) - (2x+1)2
a. x+1/x-2 - x/x+2 + 8/x2 -4
b. x-3/x+1 - x+2/x-1 + 8x/x2 -1
c. x+2/x2-2x + 2/x2+2x + 3x+2/x2-4
d. 4/x - 12/x2+3x + 5/x+3
Tìm x biết:
a) (x+5).(2x+1)=0
b) x.(x+2)-3.(x+2)=0
c) 2x.(x-5)-x.(3+2x)=26
d) x2-10x-8x+16=0
e) x2-10x=25
f) 5x.(x-1)=x-1
g) 2.(x+5)-x2-5x=0
h) x2+5x-6=0
i) (2x-3)2-4.(x+1).(x-1)=49
j) x3+x2+x+1=0
k) x3-x2=4x2-8x+4
Mn ơi giúp em vs ạ,em cảm ơn trc ạ
Ví dụ 1 (30s): Cho đa thức f(x) = (2x + 1)(x
2 − x + 1). Kết quả của phép chia đa thức f(x)
cho đa thức 2x + 1 là:
A. x
2 + x + 1 B. x
2 − x C. x
2 − x + 1 D. x
2 + 1
1, rút gọn biểu thứca, [(3x - 2)(x + 1) - (2x + 5)(x2 - 1)] : (x + 1)b, (2x + 1)^2 - 2(2x + 1)(3 - x) + (3 - x)^2c, (x - 1)^3 - (x + 1) (x2 - x + 1) - (3x + 1)(1 - 3x)
Xem chi tiết
Tìm x:
a) x(x+1)(x+2)(x+3) = (x2+3x+1)2+x
b) (x+1)(x+3)(x+5)(x+7) = (x2+8x+11)2+2x
c) (x2-x+1)(x2+x+1)(x-1)(x+1)=63
a. x2(x – 2x3) b. (x2 + 1)(5 – x) c. (x – 2)(x2 + 3x – 4) d. (x – 2)(x – x2 + 4) e. (x2 – 1)(x2 + 2x) f. (2x – 1)(3x + 2)(3 – x) g. (x + 3)(x2 + 3x – 5) h. (xy – 2).(x3 – 2x – i. (5x3 – x2 + 2x – 3).(4x2 – x + 2
tìm x:
a)3(2x-3)+2(2-x)=-3
b)2x(x2-2)+x2(1-2x)-x2=-12
c)3x(2x+3)-(2x+5)(3x-2)=8
d)4x(x - 1) - 3(x2-5)-x2=(x-3)-(x+4)
e)2(3x-1)(2x+5)-6(2x-1)(x+2)=-6