Question

(x-1)^x+2=(x-1)^x+6

 

Answer 1

mk trả lời giống nguyen minh dat

Answer 2

\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+6}\Leftrightarrow\left(x-1\right)^{x+6}-\left(x-1\right)^{x+2}=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\left(\left(x-1\right)^4-1\right)=0\)

=> x -1 =0 => x =1

hoặc (x-1)⁴ =1 => x -1 =1 => x =2

                        hoặc x -1 =-1 => x =0

Vậy x thuộc { 0;1;2}

Answer 3

(x-1)^x+2 = (x-1)^x+6 

=> (x-1)^x . (x-1)² = (x-1)^x . (x-1)⁶ 

=> (x-1)² = (x-1)⁶

=> (x-1)⁶:(x-1)² = 1

=> (x-1)⁴ = 1

=> (x-1)⁴ = 1⁴ hoac (-1)⁴

=> x = 2  hoac 0

Vay: x = 2  hoac x=0