Question

x-1/2020+x-2/2019+x-3/2018+3=0

Answer 1

sửa đề -3 

\(\dfrac{x-1}{2020}-1+\dfrac{x-2}{2019}-1+\dfrac{x-3}{2018}-1=0\)

\(\Leftrightarrow\dfrac{x-2021}{2020}+\dfrac{x-2021}{2019}+\dfrac{x-2021}{2018}=0\)

\(\Leftrightarrow\left(x-2021\right)\left(\dfrac{1}{2020}+\dfrac{1}{2019}+\dfrac{1}{2018}\right)=0\Leftrightarrow x=2021\)

Answer 2

\(\dfrac{x-1}{2020}+\dfrac{x-2}{2019}+\dfrac{x-3}{2018}-3=0\)

\(\Rightarrow\left(\dfrac{x-1}{2020}-1\right)+\left(\dfrac{x-2}{2019}-1\right)+\left(\dfrac{x-3}{2018}-1\right)=0\)

\(\Rightarrow\dfrac{x-2021}{2020}+\dfrac{x-2021}{2019}+\dfrac{x-2021}{2018}=0\)

\(\Rightarrow\left(x-2021\right)\left(\dfrac{1}{2020}+\dfrac{1}{2019}+\dfrac{1}{2018}\right)=0\)

\(\Rightarrow x-2021=0\Rightarrow x=2021\)