\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
⇔\(7\left(x-1\right)=6\left(x+5\right)\)
⇔\(7x-7=6x+30\)
⇔\(7x-7-6x-30=0\)
⇔\(x-37=0\)
⇔\(x=37\)
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\left(đk:x\ne-5\right)\)
\(\Rightarrow7\left(x-1\right)=6\left(x+5\right)\)
\(\Rightarrow7x-7=6x+30\)
\(\Rightarrow x=37\left(tm\right)\)
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7x-35=6x-6\)
hay x=29
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Rightarrow6.\left(x+5\right)=7.\left(x-1\right)\)
\(\Rightarrow6x+30=7x-7\)
\(\Rightarrow30+7=7x-6x\)
\(\Rightarrow x=37\)
