\(3^2\cdot4^3-3^2+333\)
\(=3^2\left(4^3-1\right)+333\)
\(=3^2\cdot63+333\)
\(=3^4\cdot7+3^2\cdot37\)
\(=3^2\left(63+37\right)\)
\(=30^2\)
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B=32⋅43−32+333
B=32(43−1)+333
B=32⋅63+333
B=34⋅7+32⋅37
B=32(63+37)
B=302
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