Question

Viết đa thức sau dưới dạng tích: 1/4a^2+2ab^2+4b^4

Answer 1

       \(\dfrac{1}{4}a^2+2ab^2+4b^4\)

   =  \(\left(\dfrac{1}{2}a\right)^2+2\cdot a\cdot\dfrac{1}{2}+\left(2b\right)^2\)

   = \(\left(\dfrac{1}{2}a+2b\right)^2\)

   = \(\left(\dfrac{1}{2}a+2b\right)\cdot\left(\dfrac{1}{2}a+2b\right)\)