Question

Viết các hiệu bình phương thành dạng tích:

a,   x^2 - ( y - 2 )^2

b,   (2x + 5)^2 - (y - 3)^2

ai làm đúng mik cho hai tick

 

Answer 1

\(a,x^2-\left(y-2\right)^2=\left(x-y+2\right)\left(x+y-2\right)\)

\(b,\left(2x+5\right)^2-\left(y-3\right)^2=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)

\(=\left(2x-y+8\right)\left(2x+y+2\right)\)

Answer 2

a) \(x^2-\left(y-2\right)^2\)

\(=\left(x-y+2\right)\left(x+y-2\right)\)

b) \(\left(2x+5\right)^2-\left(y-3\right)^2\)

\(=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)

\(=\left(2x-y+8\right)\left(2x+y+2\right)\)

Answer 3

\(a,x^2-\left(y-2\right)^2\)

\(=\left(x-y+2\right)\left(x+y-2\right)\)

\(b,\left(2x+5\right)^2-\left(y-3\right)^2\)

\(=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)

\(=\left(2x-y+8\right)\left(2x+y+2\right)\)

Answer 4

a)\(x^2-\left(y-2\right)^2=\left(x+y-2\right)\left(x-y+2\right)\)

b)\(\left(2x+5\right)^2-\left(y-3\right)^2=\left(2x+5+y-3\right)\left(2x+5-y+3\right)=\left(2x+y+2\right)\left(2x-y+8\right)\)

Answer 5

\(a,x^2-\left(y-2\right)^2\)

\(=\left(x-y+2\right)\left(x+y-2\right)\)

\(b,\left(2x+5\right)^2-\left(y-3\right)^2\)

\(=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)

\(=\left(2x-y+8\right)\left(2x+y+2\right)\)