Question

viết các biểu thức sau thành hằng đẳng thức: 2.(3+1).(3^2+1).(3^4+1)

Answer 1

\(2.\left(3+1\right).\left(3^2+1\right).\left(3^4+1\right)\)

= \(\left(6+2\right)\left(3^2+1\right)\left(3^4+1\right)\)

= \(\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)

= \(\left(3^4-1\right)\left(3^4+1\right)\)

= \(3^8-1\)

Chúc bạn học tốt !!!

Answer 2

\(2\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3^4-1\right)\left(3^4+1\right)\)

\(=3^8-1\)

Answer 3

$2.\left(3+1\right).\left({}^{}+1\right).\left({}^{}+1\right)$

= $\left(6+2\right)\left({}^{}+1\right)\left({}^{}+1\right)$

= $\left({}^{}-1\right)\left({}^{}+1\right)\left({}^{}+1\right)$

= $\left({}^{}-1\right)\left({}^{}+1\right)$

= ${}^{}-1$

Chúc bạn học tốt !!