\(\frac{1}{2}x+150\%x=2014\)
\(\frac{1}{2}x+\frac{3}{2}x=2014\)
\(\left(\frac{1}{2}+\frac{3}{2}\right).x=2014\)
\(2.x=2014\)
\(\Rightarrow x=1007\)
\(\frac{1}{2}x+150\%x=2014\)
=>\(\frac{1}{2}x+\frac{3}{2}x=2014\)
=>x(\(\frac{1}{2}+\frac{3}{2}\))=2014
=>x.2=2014
=>x=1007
vậy x=1007
\(\frac{1}{2}x+150\%x=2014\)
=> \(\frac{1}{2}x+\frac{3}{2}x=2014\)
=> \(\left(\frac{1}{2}+\frac{3}{2}\right)x=2014\)
=> \(2x=2014\)
=> \(x=2014:2\)
=> \(x=1007\)